description

# parse method

double parse (String source, [ @deprecated double onError(String source) ])
override

Parse `source` as an double literal and return its value.

Accepts an optional sign (`+` or `-`) followed by either the characters "Infinity", the characters "NaN" or a floating-point representation. A floating-point representation is composed of a mantissa and an optional exponent part. The mantissa is either a decimal point (`.`) followed by a sequence of (decimal) digits, or a sequence of digits optionally followed by a decimal point and optionally more digits. The (optional) exponent part consists of the character "e" or "E", an optional sign, and one or more digits. The `source` must not be `null`.

Leading and trailing whitespace is ignored.

If the `source` string is not a valid double literal, the `onError` is called with the `source` as argument, and its return value is used instead. If no `onError` is provided, a FormatException is thrown instead.

The `onError` function is only invoked if `source` is a String with an invalid format. It is not invoked if `source` is `null`.

Examples of accepted strings:

    "3.14"
    "  3.14 \xA0"
    "0."
    ".0"
    "-1.e3"
    "1234E+7"
    "+.12e-9"
    "-NaN"

The `onError` parameter is deprecated and will be removed. Instead of `double.parse(string, (string) { ... })`, you should use `double.tryParse(string) ?? (...)`.

## Implementation

    external static double parse(String source,
        [@deprecated double onError(String source)]);