# Functions

Every Rust program has at least one function, the `main` function:

fn main() { }

    fn main() {
    }

This is the simplest possible function declaration. As we mentioned before, `fn` says ‘this is a function’, followed by the name, some parentheses because this function takes no arguments, and then some curly braces to indicate the body. Here’s a function named `foo`:

fn main() { fn foo() { } }

    fn foo() {
    }

So, what about taking arguments? Here’s a function that prints a number:

fn main() { fn print_number(x: i32) { println!("x is: {}", x); } }

    fn print_number(x: i32) {
        println!("x is: {}", x);
    }

Here’s a complete program that uses `print_number`:

fn main() { print_number(5); } fn print_number(x: i32) { println!("x is: {}", x); }

    fn main() {
        print_number(5);
    }

    fn print_number(x: i32) {
        println!("x is: {}", x);
    }

As you can see, function arguments work very similar to `let` declarations: you add a type to the argument name, after a colon.

Here’s a complete program that adds two numbers together and prints them:

fn main() { print_sum(5, 6); } fn print_sum(x: i32, y: i32) { println!("sum is: {}", x + y); }

    fn main() {
        print_sum(5, 6);
    }

    fn print_sum(x: i32, y: i32) {
        println!("sum is: {}", x + y);
    }

You separate arguments with a comma, both when you call the function, as well as when you declare it.

Unlike `let`, you must declare the types of function arguments. This does not work:

fn main() { fn print_sum(x, y) { println!("sum is: {}", x + y); } }

    fn print_sum(x, y) {
        println!("sum is: {}", x + y);
    }

You get this error:

    expected one of `!`, `:`, or `@`, found `)`
    fn print_sum(x, y) {

This is a deliberate design decision. While full-program inference is possible, languages which have it, like Haskell, often suggest that documenting your types explicitly is a best-practice. We agree that forcing functions to declare types while allowing for inference inside of function bodies is a wonderful sweet spot between full inference and no inference.

What about returning a value? Here’s a function that adds one to an integer:

fn main() { fn add_one(x: i32) -> i32 { x + 1 } }

    fn add_one(x: i32) -> i32 {
        x + 1
    }

Rust functions return exactly one value, and you declare the type after an ‘arrow’, which is a dash (`-`) followed by a greater-than sign (`>`). The last line of a function determines what it returns. You’ll note the lack of a semicolon here. If we added it in:

fn main() { fn add_one(x: i32) -> i32 { x + 1; } }

    fn add_one(x: i32) -> i32 {
        x + 1;
    }

We would get an error:

    error: not all control paths return a value
    fn add_one(x: i32) -> i32 {
         x + 1;
    }

    help: consider removing this semicolon:
         x + 1;
              ^

This reveals two interesting things about Rust: it is an expression-based language, and semicolons are different from semicolons in other ‘curly brace and semicolon’-based languages. These two things are related.

## Expressions vs. Statements

Rust is primarily an expression-based language. There are only two kinds of statements, and everything else is an expression.

So what's the difference? Expressions return a value, and statements do not. That’s why we end up with ‘not all control paths return a value’ here: the statement `x + 1;` doesn’t return a value. There are two kinds of statements in Rust: ‘declaration statements’ and ‘expression statements’. Everything else is an expression. Let’s talk about declaration statements first.

In some languages, variable bindings can be written as expressions, not statements. Like Ruby:

    x = y = 5

In Rust, however, using `let` to introduce a binding is not an expression. The following will produce a compile-time error:

fn main() { let x = (let y = 5); // expected identifier, found keyword `let` }

    let x = (let y = 5); // expected identifier, found keyword `let`

The compiler is telling us here that it was expecting to see the beginning of an expression, and a `let` can only begin a statement, not an expression.

Note that assigning to an already-bound variable (e.g. `y = 5`) is still an expression, although its value is not particularly useful. Unlike other languages where an assignment evaluates to the assigned value (e.g. `5` in the previous example), in Rust the value of an assignment is an empty tuple `()` because the assigned value can have only one owner, and any other returned value would be too surprising:

fn main() { let mut y = 5; let x = (y = 6); // x has the value `()`, not `6` }

    let mut y = 5;

    let x = (y = 6);  // x has the value `()`, not `6`

The second kind of statement in Rust is the expression statement. Its purpose is to turn any expression into a statement. In practical terms, Rust's grammar expects statements to follow other statements. This means that you use semicolons to separate expressions from each other. This means that Rust looks a lot like most other languages that require you to use semicolons at the end of every line, and you will see semicolons at the end of almost every line of Rust code you see.

What is this exception that makes us say "almost"? You saw it already, in this code:

fn main() { fn add_one(x: i32) -> i32 { x + 1 } }

    fn add_one(x: i32) -> i32 {
        x + 1
    }

Our function claims to return an `i32`, but with a semicolon, it would return `()` instead. Rust realizes this probably isn’t what we want, and suggests removing the semicolon in the error we saw before.

## Early returns

But what about early returns? Rust does have a keyword for that, `return`:

fn main() { fn foo(x: i32) -> i32 { return x; // we never run this code! x + 1 } }

    fn foo(x: i32) -> i32 {
        return x;

        // we never run this code!
        x + 1
    }

Using a `return` as the last line of a function works, but is considered poor style:

fn main() { fn foo(x: i32) -> i32 { return x + 1; } }

    fn foo(x: i32) -> i32 {
        return x + 1;
    }

The previous definition without `return` may look a bit strange if you haven’t worked in an expression-based language before, but it becomes intuitive over time.

## Diverging functions

Rust has some special syntax for ‘diverging functions’, which are functions that do not return:

fn main() { fn diverges() -> ! { panic!("This function never returns!"); } }

    fn diverges() -> ! {
        panic!("This function never returns!");
    }

`panic!` is a macro, similar to `println!()` that we’ve already seen. Unlike `println!()`, `panic!()` causes the current thread of execution to crash with the given message. Because this function will cause a crash, it will never return, and so it has the type ‘`!`’, which is read ‘diverges’.

If you add a main function that calls `diverges()` and run it, you’ll get some output that looks like this:

    thread ‘main’ panicked at ‘This function never returns!’, hello.rs:2

If you want more information, you can get a backtrace by setting the `RUST_BACKTRACE` environment variable:

    $ RUST_BACKTRACE=1 ./diverges
    thread 'main' panicked at 'This function never returns!', hello.rs:2
    stack backtrace:
       1:     0x7f402773a829 - sys::backtrace::write::h0942de78b6c02817K8r
       2:     0x7f402773d7fc - panicking::on_panic::h3f23f9d0b5f4c91bu9w
       3:     0x7f402773960e - rt::unwind::begin_unwind_inner::h2844b8c5e81e79558Bw
       4:     0x7f4027738893 - rt::unwind::begin_unwind::h4375279447423903650
       5:     0x7f4027738809 - diverges::h2266b4c4b850236beaa
       6:     0x7f40277389e5 - main::h19bb1149c2f00ecfBaa
       7:     0x7f402773f514 - rt::unwind::try::try_fn::h13186883479104382231
       8:     0x7f402773d1d8 - __rust_try
       9:     0x7f402773f201 - rt::lang_start::ha172a3ce74bb453aK5w
      10:     0x7f4027738a19 - main
      11:     0x7f402694ab44 - __libc_start_main
      12:     0x7f40277386c8 - <unknown>
      13:                0x0 - <unknown>

If you need to override an already set `RUST_BACKTRACE`, in cases when you cannot just unset the variable, then set it to `0` to avoid getting a backtrace. Any other value (even no value at all) turns on backtrace.

    $ export RUST_BACKTRACE=1
    ...
    $ RUST_BACKTRACE=0 ./diverges
    thread 'main' panicked at 'This function never returns!', hello.rs:2
    note: Run with `RUST_BACKTRACE=1` for a backtrace.

`RUST_BACKTRACE` also works with Cargo’s `run` command:

    $ RUST_BACKTRACE=1 cargo run
         Running `target/debug/diverges`
    thread 'main' panicked at 'This function never returns!', hello.rs:2
    stack backtrace:
       1:     0x7f402773a829 - sys::backtrace::write::h0942de78b6c02817K8r
       2:     0x7f402773d7fc - panicking::on_panic::h3f23f9d0b5f4c91bu9w
       3:     0x7f402773960e - rt::unwind::begin_unwind_inner::h2844b8c5e81e79558Bw
       4:     0x7f4027738893 - rt::unwind::begin_unwind::h4375279447423903650
       5:     0x7f4027738809 - diverges::h2266b4c4b850236beaa
       6:     0x7f40277389e5 - main::h19bb1149c2f00ecfBaa
       7:     0x7f402773f514 - rt::unwind::try::try_fn::h13186883479104382231
       8:     0x7f402773d1d8 - __rust_try
       9:     0x7f402773f201 - rt::lang_start::ha172a3ce74bb453aK5w
      10:     0x7f4027738a19 - main
      11:     0x7f402694ab44 - __libc_start_main
      12:     0x7f40277386c8 - <unknown>
      13:                0x0 - <unknown>

A diverging function can be used as any type:

fn main() { fn diverges() -> ! { panic!("This function never returns!"); } let x: i32 = diverges(); let x: String = diverges(); }

    let x: i32 = diverges();
    let x: String = diverges();

## Function pointers

We can also create variable bindings which point to functions:

fn main() { let f: fn(i32) -> i32; }

    let f: fn(i32) -> i32;

`f` is a variable binding which points to a function that takes an `i32` as an argument and returns an `i32`. For example:

fn main() { fn plus_one(i: i32) -> i32 { i + 1 } // without type inference let f: fn(i32) -> i32 = plus_one; // with type inference let f = plus_one; }

    fn plus_one(i: i32) -> i32 {
        i + 1
    }

    // without type inference
    let f: fn(i32) -> i32 = plus_one;

    // with type inference
    let f = plus_one;

We can then use `f` to call the function:

fn main() { fn plus_one(i: i32) -> i32 { i + 1 } let f = plus_one; let six = f(5); }

    let six = f(5);